I thought about that, but in scenario where I have switched the LEDS off using the switch, the resistor will then bypass that and carry on that parasitic load won’t it? I suppose the way in my diagram if switch is off then there is no load at all. But as you say it’s going to be negligible either way.You could fit the resistor just to + and door switched -ve you don’t need a resistor for the perm -ve as it’s physically open circuit when not in use so no leakage j how you’ve drawn it above is still ok though.
I guess the other calculation is what affect the resistor has when LEDS are on in that parallel circuit… but once again I suspect it is negligible again.