There is only a single inverter in the Clayton regardless of if you are using the 3 pin socket on the front or other sockets wired to the 240v out.
Treat it as a single 13 pin plug - you wouldn't plug a hob and a kettle into a 4 plug strip and into the wall so don't expect that to work on a Clayton (and frankly the same is true of any EHU setup as they are all limited to a max of 16A by the connectors)
Every 240v appliance will have a rating plate on it listing the average draw in watts. Add those up and compare them to that rated output of the inverter. Keep to about 80% of total capacity as individual appliances vary. So if you have a 2000w / 2kw inverter don't use more than 1600w.
Be aware that any 240v appliance that has a motor or a resistive (glowing) heating element will draw quite a bit more when it switches on. Those types of devices you should probably only use one at a time if you are running off the inverter. So things like a microwave, coffee machine, hair dryer, oil radiator.
For runtime calculations then we need to account for about 80% efficiency in the inverter and the fact that the Clayton will cut off at 20% of charge to protect the battery. So for a 100aH battery you will have 80aH (100 x 0.8) of usable capacity for both the 12v and 240v systems. If you use that mostly for 240v then you will have 64aH (80 x 0.8) of usable capacity.
Then for each 100w of load you will use around 8aH (100w / 12v) of capacity per hour. For example a 2kw kettle would use ( 2000 / 100 ) x 8 = 160aH if left on for an hour; however if we assume 5 minutes than boiling a kettle will use (160 / 60) x 5 = 13.5aH
If you're now thinking "but that means I can only boil the kettle around 4 times before the battery is empty" - you're right. 240v heating appliances consume an enormous amount of power, you just don't notice it until you have to generate that power yourself.
A Clayton with a 2500w inverter and a 100aH battery has about 20 minutes of run time at full power on 240v. It will then take about 2 hours to recharge off engine, probably around 1.5 hours off EHU.
Treat it as a single 13 pin plug - you wouldn't plug a hob and a kettle into a 4 plug strip and into the wall so don't expect that to work on a Clayton (and frankly the same is true of any EHU setup as they are all limited to a max of 16A by the connectors)
Every 240v appliance will have a rating plate on it listing the average draw in watts. Add those up and compare them to that rated output of the inverter. Keep to about 80% of total capacity as individual appliances vary. So if you have a 2000w / 2kw inverter don't use more than 1600w.
Be aware that any 240v appliance that has a motor or a resistive (glowing) heating element will draw quite a bit more when it switches on. Those types of devices you should probably only use one at a time if you are running off the inverter. So things like a microwave, coffee machine, hair dryer, oil radiator.
For runtime calculations then we need to account for about 80% efficiency in the inverter and the fact that the Clayton will cut off at 20% of charge to protect the battery. So for a 100aH battery you will have 80aH (100 x 0.8) of usable capacity for both the 12v and 240v systems. If you use that mostly for 240v then you will have 64aH (80 x 0.8) of usable capacity.
Then for each 100w of load you will use around 8aH (100w / 12v) of capacity per hour. For example a 2kw kettle would use ( 2000 / 100 ) x 8 = 160aH if left on for an hour; however if we assume 5 minutes than boiling a kettle will use (160 / 60) x 5 = 13.5aH
If you're now thinking "but that means I can only boil the kettle around 4 times before the battery is empty" - you're right. 240v heating appliances consume an enormous amount of power, you just don't notice it until you have to generate that power yourself.
A Clayton with a 2500w inverter and a 100aH battery has about 20 minutes of run time at full power on 240v. It will then take about 2 hours to recharge off engine, probably around 1.5 hours off EHU.